Statistics Class 11 Chapter 9 - Binomial & Hyper Geometric Probability Distribution - Solved MCQs for All Exam Boards

"THE HOLY QURAN AND STATISTICS"
Surah Al-Jinn (72:28):
وَأَحْصَىٰ كُلَّ شَيْءٍ عَدَدًا

"And He has enumerated everything in numbers." (Allah perfectly counts and knows the exact measure of all creations).

(F.Sc. Part – I, Chapter 9: Binomial & Hyper-Geometric Distribution)

Q1. A Bernoulli trial has only:

A. Two outcomes   ✓ Correct Answer

B. Three outcomes

C. Four outcomes

D. Unlimited outcomes

Explanation: A Bernoulli trial is defined as a random experiment with exactly two possible outcomes — success or failure.

Q2. If a Bernoulli trial is repeated independently n > 1 times, it becomes a(n):

A. Hypergeometric experiment

B. Undefined experiment

C. Binomial experiment   ✓ Correct Answer

D. Dependent experiment

Explanation: Repeating independent Bernoulli trials n times, with a fixed probability of success, defines a binomial experiment.

Q3. If n = 1 in a Binomial distribution, then it becomes a:

A. Uniform Distribution

B. Hypergeometric Distribution

C. Bernoulli Distribution   ✓ Correct Answer

D. None

Explanation: A single binomial trial (n=1) is exactly the same as a single Bernoulli trial.

Q4. Throwing a coin once is an example of a:

A. Binomial experiment

B. Bernoulli trial   ✓ Correct Answer

C. Hypergeometric experiment

D. None

Explanation: A single coin toss has only two outcomes (heads/tails), making it a Bernoulli trial rather than a full binomial experiment (which needs repeated trials).

Q5. A paper has 15 multiple choice questions with 3 alternatives; answering these by guesswork follows a:

A. Binomial Distribution   ✓ Correct Answer

B. Uniform Distribution

C. Hypergeometric Distribution

D. None

Explanation: Each question is an independent trial with a fixed probability of guessing correctly, matching the binomial setup.

Q6. A random sample chosen with replacement from a finite population follows a:

A. Dependent sample

B. Binomial Distribution   ✓ Correct Answer

C. Hypergeometric Distribution

D. None

Explanation: Sampling with replacement keeps trials independent with constant probability, which is exactly the binomial setup.

Q7. Successive trials being independent is characteristic of:

A. Binomial Distribution

B. Selection with replacement

C. Hypergeometric Distribution

D. Both (a) and (b)   ✓ Correct Answer

Explanation: Both the binomial distribution and sampling with replacement rely on independent successive trials.

Q8. The probability of success remaining constant at each trial is characteristic of:

A. Hypergeometric Distribution

B. Dependent trials

C. Binomial Distribution   ✓ Correct Answer

D. Selection without replacement

Explanation: A defining feature of the binomial distribution is that the probability of success stays fixed across all trials.

Q9. The Binomial distribution is applicable when successive trials are:

A. Done with replacement

B. Independent

C. Dependent

D. Both (a) and (b)   ✓ Correct Answer

Explanation: Binomial trials require both independence and (typically achieved via) sampling with replacement.

Q10. Tossing a fair coin 8 times is an example of a:

A. Binomial experiment   ✓ Correct Answer

B. Uniform experiment

C. Hypergeometric experiment

D. None

Explanation: Each toss is an independent trial with a fixed probability of heads, making repeated tosses a binomial experiment.

Q11. Drawing two cards with replacement is an example of a:

A. Uniform experiment

B. Binomial experiment   ✓ Correct Answer

C. Hypergeometric experiment

D. None

Explanation: Replacing the card after each draw keeps trials independent and probabilities fixed — a binomial setup.

Q12. In a Binomial distribution, n (the number of trials) is:

A. Fixed   ✓ Correct Answer

B. Infinite

C. Unlimited

D. Not fixed

Explanation: The number of trials, n, is always a fixed, pre-determined value in a binomial distribution.

Q13. In a Binomial Distribution, each trial has:

A. Four outcomes

B. Three outcomes

C. Two outcomes   ✓ Correct Answer

D. Unlimited outcomes

Explanation: Each trial in a binomial setting is Bernoulli-like, having exactly two possible outcomes.

Q14. The type of Binomial Distribution is:

A. Mixed

B. Continuous

C. Discrete   ✓ Correct Answer

D. None

Explanation: Since the binomial random variable counts whole-number successes, it is a discrete distribution.

Q15. A binomial random variable (with n trials) can take:

A. n+1 possible values   ✓ Correct Answer

B. n possible values

C. n-1 possible values

D. None

Explanation: A binomial variable can take values 0, 1, 2, ..., n — that's n+1 distinct possible values.

Q16. In a Binomial Distribution, the total number of successes in n trials is at most:

A. -n

B. n   ✓ Correct Answer

C. n-1

D. n+1

Explanation: The maximum possible number of successes in n trials is n itself.

Q17. In a Binomial Distribution, (q + p)ⁿ =

A. 0

B. -1

C. 1   ✓ Correct Answer

D. Zero

Explanation: Since p + q = 1 (probabilities of success and failure sum to 1), raising it to any power n still gives 1.

Q18. In a Binomial Distribution, np(q + p)ⁿ =

A. np(q+p)ⁿ⁺¹

B. np   ✓ Correct Answer

C. 1

D. Zero

Explanation: Since (q+p)ⁿ = 1, multiplying by np simply gives np.

Q19. A binomial random variable can take only:

A. Non-negative values   ✓ Correct Answer

B. Negative values

C. Fractional values

D. None

Explanation: Since it counts successes, a binomial variable can only take whole, non-negative values (0, 1, 2, ...).

Q20. If X ~ b(x; 5, 0.6), then P(X = 1/2) =

A. 1.2

B. 5

C. 5.6

D. Zero   ✓ Correct Answer

Explanation: A binomial variable can only take integer values, so P(X = 1/2), a non-integer, is zero.

Q21. If X ~ b(x; 5, 0.6), then P(X = -2) =

A. 1.2

B. 0.96

C. 0.30

D. Zero   ✓ Correct Answer

Explanation: A binomial variable can never be negative, so P(X = -2) is zero.

Q22. In the binomial expansion (4/5 + 1/5)⁶, n =

A. 6   ✓ Correct Answer

B. 4/5

C. 1/5

D. 1

Explanation: The exponent in the binomial expansion directly represents n, the number of trials — here n = 6.

Q23. The Binomial distribution has how many parameters?

A. One

B. Two   ✓ Correct Answer

C. Three

D. Four

Explanation: The binomial distribution is fully defined by two parameters: n (number of trials) and p (probability of success).

Q24. In a Binomial Distribution, ⁷C₄(1/3)⁴(2/3)⁷⁻⁴, then p =

A. 1/3   ✓ Correct Answer

B. 2/3

C. 7

D. ⁷C₄

Explanation: By convention, p is the probability of success, which here corresponds to the (1/3) term raised to the number of successes (4).

Q25. The shape of the binomial distribution depends upon the:

A. Number of trials

B. Probability of success

C. Both (a) and (b)   ✓ Correct Answer

D. Values of the variable

Explanation: Both n (number of trials) and p (probability of success) jointly determine the shape of the binomial distribution.

Q26. If p = q = 1/2, the Binomial Distribution is:

A. Asymmetrical

B. Skewed

C. Not symmetrical

D. Symmetrical   ✓ Correct Answer

Explanation: When success and failure are equally likely (p=q=1/2), the binomial distribution is perfectly symmetrical.

Q27. If p ≠ q, the Binomial Distribution is:

A. Asymmetrical

B. Skewed

C. Symmetrical

D. Both (a) and (b)   ✓ Correct Answer

Explanation: Unequal probabilities of success and failure make the distribution both asymmetrical and skewed — the same idea.

Q28. If p > 1/2, the Binomial Distribution is:

A. Positively skewed

B. Negatively skewed   ✓ Correct Answer

C. Symmetrical

D. None

Explanation: When success is more likely than failure (p>1/2), the distribution's longer tail points toward smaller values — negatively skewed.

Q29. If p < 1/2, the Binomial Distribution is:

A. Positively skewed   ✓ Correct Answer

B. Negatively skewed

C. Symmetrical

D. None

Explanation: When success is less likely than failure (p<1/2), the distribution's longer tail points toward larger values — positively skewed.

Q30. If p < q in a Binomial distribution, then:

A. Mean = median = mode

B. Mean > median > mode   ✓ Correct Answer

C. Mean < median < mode

D. None

Explanation: p<q means p<1/2, giving a positively skewed distribution, where mean > median > mode.

Q31. If p > q in a Binomial distribution, then:

A. Mean = median = mode

B. Mean > median > mode

C. Mean < median < mode   ✓ Correct Answer

D. None

Explanation: p>q means p>1/2, giving a negatively skewed distribution, where mean < median < mode.

Q32. The mean, median, and mode of a Binomial distribution are equal if:

A. p = q = 1/2   ✓ Correct Answer

B. p < 1/2

C. p > 1/2

D. None

Explanation: Only when the distribution is perfectly symmetrical (p=q=1/2) do mean, median, and mode all coincide.

Q33. Mean > Median > Mode in a Binomial distribution if:

A. p = q = 1/2

B. p < 1/2   ✓ Correct Answer

C. p > 1/2

D. None

Explanation: A positively skewed distribution (which occurs when p<1/2) has the ordering mean > median > mode.

Q34. Mean < Median < Mode in a Binomial distribution if:

A. p = q = 1/2

B. p < 1/2

C. p > 1/2   ✓ Correct Answer

D. None

Explanation: A negatively skewed distribution (which occurs when p>1/2) has the ordering mean < median < mode.

Q35. In a Binomial distribution, the mean is:

A. Greater than the variance   ✓ Correct Answer

B. Less than the variance

C. Equal to the variance

D. None

Explanation: Since mean = np and variance = npq with q<1, the variance (npq) is always smaller than the mean (np).

Q36. The standard deviation of a Binomial Distribution is:

A. npq

B. np

C. √(npq)   ✓ Correct Answer

D. None

Explanation: Standard deviation is the square root of variance, and variance of a binomial distribution is npq.

Q37. The mean of the Binomial distribution is:

A. np   ✓ Correct Answer

B. n/p

C. p/n

D. None

Explanation: The mean of a binomial distribution is given by np (number of trials × probability of success).

Q38. A Binomial variable with n = 6, p = 0.2 has the standard deviation:

A. 0.2

B. 0.98   ✓ Correct Answer

C. 1.2

D. 0.33

Explanation: S.D. = √(npq) = √(6 × 0.2 × 0.8) = √0.96 ≈ 0.98.

Q39. The mean of (q + p)ⁿ is:

A. np   ✓ Correct Answer

B. n/p

C. p/n

D. None

Explanation: Since (q+p)ⁿ represents the binomial expansion, its associated mean is np.

Q40. The variance of (q + p)ⁿ is:

A. npq   ✓ Correct Answer

B. nq/p

C. p/nq

D. None

Explanation: The variance associated with the binomial expansion (q+p)ⁿ is npq.

Q41. ⁿCₓ πˣ(1-π)ⁿ⁻ˣ is called the Binomial:

A. Probability distribution   ✓ Correct Answer

B. Frequency distribution

C. Cumulative distribution

D. None

Explanation: This formula is the probability mass function of the binomial probability distribution.

Q42. The mean of (q + p)³ is:

A. 3p   ✓ Correct Answer

B. n/p

C. p/n

D. None

Explanation: For n=3, the mean of the binomial expansion is np = 3p.

Q43. The variance of (q + p)³ is:

A. 3pq   ✓ Correct Answer

B. nq/p

C. p/nq

D. None

Explanation: For n=3, the variance of the binomial expansion is npq = 3pq.

Q44. In a Binomial Distribution with n = 4 and p = 1/2, P(X = 5) =

A. 1/2

B. 1/3

C. 2/3

D. Zero   ✓ Correct Answer

Explanation: Since n=4, X can only range from 0 to 4 — X=5 is impossible, so its probability is zero.

Q45. A hypergeometric experiment is one that consists of n Bernoulli trials that are:

A. Dependent trials

B. Independent trials

C. Without replacement trials

D. Both (a) and (c)   ✓ Correct Answer

Explanation: Hypergeometric trials involve sampling without replacement, which makes successive trials dependent on each other.

Q46. In a Hypergeometric Distribution, each trial has:

A. Two outcomes   ✓ Correct Answer

B. Three outcomes

C. Four outcomes

D. None

Explanation: Like the binomial, each trial in a hypergeometric setting has just two outcomes: success or failure.

Q47. Both Binomial and Hypergeometric distributions are:

A. Mixed

B. Continuous

C. Discrete   ✓ Correct Answer

D. None

Explanation: Since both distributions count whole-number successes, they are discrete probability distributions.

Q48. A changing probability of success at each trial is characteristic of:

A. Binomial Distribution

B. Uniform Distribution

C. Hypergeometric Distribution   ✓ Correct Answer

D. Selection with replacement

Explanation: Because sampling is done without replacement, the probability of success changes after each draw in a hypergeometric setting.

Q49. Successive trials being dependent is characteristic of:

A. Binomial Distribution

B. Selection without replacement

C. Hypergeometric Distribution

D. Both (b) and (c)   ✓ Correct Answer

Explanation: Selection without replacement (the basis of the hypergeometric distribution) makes each trial dependent on the previous ones.

Q50. Drawing two cards without replacement follows a:

A. Binomial Distribution

B. Uniform Distribution

C. Hypergeometric Distribution   ✓ Correct Answer

D. None

Explanation: Without replacement, the composition of the deck changes between draws — the hallmark of a hypergeometric setup.

Q51. A probability of success that varies from trial to trial is characteristic of:

A. Binomial Distribution

B. Uniform Distribution

C. Hypergeometric Distribution   ✓ Correct Answer

D. None

Explanation: Unlike the binomial (constant p), the hypergeometric distribution has a probability of success that changes with each trial.

Q52. Successive trials being without replacement is characteristic of:

A. Hypergeometric Distribution   ✓ Correct Answer

B. Uniform Distribution

C. Binomial Distribution

D. None

Explanation: Sampling without replacement is exactly the defining condition of the hypergeometric distribution.

Q53. A random sample chosen without replacement from a finite population follows a:

A. Binomial Distribution

B. Uniform Distribution

C. Hypergeometric Distribution   ✓ Correct Answer

D. None

Explanation: Without-replacement sampling from a finite population is the defining scenario for the hypergeometric distribution.

Q54. A random sample chosen by selecting all items at once from a finite population follows a:

A. Binomial Distribution

B. Hypergeometric Distribution   ✓ Correct Answer

C. Uniform Distribution

D. None

Explanation: Selecting an entire sample at once (equivalent to without replacement) corresponds to the hypergeometric distribution.

Q55. The Hypergeometric Distribution has how many parameters?

A. One

B. Two

C. Three   ✓ Correct Answer

D. Four

Explanation: The hypergeometric distribution is defined by three parameters: N (population size), n (sample size), and k (number of successes in the population).

Q56. The mean of the Hypergeometric Distribution is:

A. nk/N   ✓ Correct Answer

B. N/nk

C. (nk/N)[(N-k)/N]

D. None

Explanation: The mean of a hypergeometric distribution is given by nk/N.

Q57. The variance of the Hypergeometric Distribution is:

A. (nk/N)[(N-k)/N][(N-n)/(N-1)]   ✓ Correct Answer

B. N/nk

C. nk/N

D. None

Explanation: This is the standard formula for the variance of a hypergeometric distribution, incorporating the finite population correction.

Q58. The standard deviation of the Hypergeometric Distribution is:

A. Np

B. √{(nk/N)[(N-k)/N][(N-n)/(N-1)]}   ✓ Correct Answer

C. npq

D. None

Explanation: Standard deviation is the square root of the hypergeometric variance formula.

Q59. If X ~ h(x; N, n, k), the mean is:

A. nk/N   ✓ Correct Answer

B. np

C. npq

D. None

Explanation: For a hypergeometric random variable, the mean is given by nk/N.

Q60. Which of the following is NOT an assumption of the Binomial distribution?

A. All trials must be dependent   ✓ Correct Answer

B. Each trial must be classified as a success or a failure

C. The number of successes in the trials is counted

D. Probability of success remains fixed

Explanation: The binomial distribution actually requires INDEPENDENT trials — so 'all trials must be dependent' is the false statement, not an actual assumption.

Q61. Suppose 60% of a group of rats is infected with a disease. Let X = the number of diseased rats in a sample of size 5. The distribution of X is:

A. Binomial with n=5 and p=0.6   ✓ Correct Answer

B. Binomial with n=5 and p=0.4

C. Binomial with n=5 and p=0.5

D. The same as the distribution of the number of uninfected rats

Explanation: Since each rat is independently infected with probability 0.6, and we're counting successes in 5 trials, X follows Binomial(n=5, p=0.6).


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